题解 | #牛牛学数列2#
牛牛学数列2
https://www.nowcoder.com/practice/fc72951f52984f3abd286d82eeffacba
#include <stdio.h>
int main()
{
float n;
double sum = 0.0;//如果是float 来定义的话，精度可能不够，所以需要用上double
scanf("%f", &n);
if (n > 1000 || n < 0)
return 0;
for (int i = 1; i <= n; i++)
{
sum += 1.0 / i;
}
printf("%.6lf", sum);
return 0;
}
