题解 | #提取不重复的整数#

#include <stdio.h>

int main() {
    int num;
    char arr[32] = {0};
    scanf("%d", &num);//113288

    int remain;
    int n=0;
    do {
        remain = num%10;
        arr[n++] = remain;//882311
    } while((num /= 10) > 0);

    //去重，因为数字只有0-9，所以可以通过标志法去重
    char flag[10] = {0};
    int i = 0;
    for (i = 0; i < n; i++) {
        if (flag[arr[i]] == 0) {
            printf("%u", arr[i]);
            flag[arr[i]] = 1;
        }
    }
}