题解 | #二分查找-I#
二分查找-I
https://www.nowcoder.com/practice/d3df40bd23594118b57554129cadf47b
import java.util.*; public class Solution { /** * 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可 * * * @param nums int整型一维数组 * @param target int整型 * @return int整型 */ public int search (int[] nums, int target) { // write code here int n = nums.length; if(n==0){ return -1; } int left =0,right = n-1; while(left<=right){ int mid = (left+right)/2; if(target>nums[mid]){ left = mid+1; }else if(target<nums[mid]){ right = mid-1; }else{ return mid; } } return -1; } }
这里要注意是 left<=right,当数组的长度为1时就会出现left和right都是0,所以不能简单的使用<