题解 | #简单密码#
简单密码
https://www.nowcoder.com/practice/7960b5038a2142a18e27e4c733855dac
while True:
try:
A="abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789"
B="22233344455566677778889999bcdefghijklmnopqrstuvwxyza0123456789"#多对一的思路重复几次数字
list1=[]
list2=[]
for i in A:
list1.append(i)
for i in B:
list2.append(i)
C=[]
a=input()
for i in a:
if i in list1:
C.append(list2[list1.index(i)])#列表的元素索引
else:
C.append(i)
print(''.join(C))
except:
break
