题解 | #反转链表#
反转链表
https://www.nowcoder.com/practice/75e878df47f24fdc9dc3e400ec6058ca
# class ListNode:
# def __init__(self, x):
# self.val = x
# self.next = None
#
# 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
#
#
# @param head ListNode类
# @return ListNode类
#
class Solution:
def ReverseList(self , head: ListNode) -> ListNode:
pre = None
current = head
while current is not None:
temp=current.next
current.next=pre
pre=current
current=temp
return pre
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