题解 | #环形链表的约瑟夫问题#
环形链表的约瑟夫问题
https://www.nowcoder.com/practice/41c399fdb6004b31a6cbb047c641ed8a
/**
* 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
*
*
* @param n int整型
* @param m int整型
* @return int整型
*/
typedef struct ListNode ListNode;
ListNode* buynode(int x)
{
ListNode* node = (ListNode*)malloc(sizeof(ListNode));
if(node == NULL)
{
exit(1);
}
node->val = x;
node->next = NULL;
return node;
}
ListNode* createcic(int n)
{
//创建第一个节点
ListNode* phead = buynode(1);
ListNode* ptail = phead;
for(int i = 2;i <= n;i++)
{
ptail->next = buynode(i);
ptail = ptail->next;
}
ptail->next = phead;
return ptail;
}
int ysf(int n, int m )
{
//1.创建带环链表
ListNode* prev = createcic(n);
//2.遍历链表,删除节点
ListNode* pcur = prev->next;
int count = 1;
while(pcur->next != pcur)
{
if(count == m)
{
prev->next = pcur->next;
free(pcur);
pcur = prev->next;
count = 1;
}
else
{
prev = pcur;
pcur = pcur->next;
count++;
}
}
return pcur->val;
}


