题解 | #牛牛的特殊数字#

from re import T
#
# 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
#
# 
# @param num int整型 
# @return bool布尔型
#
class Solution:
    def isSpecialNumber(self , num: int) -> bool:
        num = list(map(int, list(str(num))))
        flag = 0
        left = 0
        right = len(num)-1
        while left < right-1:
            # print(num)
            if num[left] != num[right]:
                if num[left] == 1:
                # x2 = [1, num[right]]
                    num[right-1] -= 1
                    num[left+1] -= num[right]
                    if num[right-1]<0 or num[left+1]<0:
                        flag = 1
                        break
                else:
                    num[left] -= num[right]
                    if num[left] != 1:
                        flag = 1
                        break
            left += 1
            right -= 1
        if flag==0 and (left == right or num[right]%2==0):
            return True
        else:
            return False