题解 | #删除字符串中出现次数最少的字符#
删除字符串中出现次数最少的字符
https://www.nowcoder.com/practice/05182d328eb848dda7fdd5e029a56da9
s1=input()
se1=set(s1)
li2=list(se1)
#print(li2)
li=[]
for i in se1:
n=0
for j in s1 :
if i==j:
n+=1
li.append(n)
min1=min(li)
#print(min1)
li1=[]
dic1={k:v for k,v in zip(li2,li)}
#print(dic1)
for i in dic1.items():
if i[1]==min1:
li1.append(i[0])
for i in li1:
s1=s1.replace(i,'')
print(s1)
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