题解 | #牛牛的单链表求和#
牛牛的单链表求和
https://www.nowcoder.com/practice/a674715b6b3845aca0d5009bc27380b5
#include <stdio.h>
#include<malloc.h>
typedef struct node {
int data;
struct node* next;
} node;
int main() {
int n, sum = 0;
scanf("%d", &n);
node* head = malloc(sizeof(node)), *t = head;
while (n--) {
scanf("%d", &t->data);
node* node = malloc(sizeof(node));
t->next = node;
t = t->next;
}
while (head->next) {
sum += head->data;
head = head->next;
}
printf("%d\n", sum);
return 0;
}
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