题解 | #牛牛的单链表求和#
牛牛的单链表求和
https://www.nowcoder.com/practice/a674715b6b3845aca0d5009bc27380b5
#include <stdio.h> #include<malloc.h> typedef struct node { int data; struct node* next; } node; int main() { int n, sum = 0; scanf("%d", &n); node* head = malloc(sizeof(node)), *t = head; while (n--) { scanf("%d", &t->data); node* node = malloc(sizeof(node)); t->next = node; t = t->next; } while (head->next) { sum += head->data; head = head->next; } printf("%d\n", sum); return 0; }#C#
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