题解 | #小乐乐改数字#

#include <stdio.h>
#include <math.h>

int main() {
    int arr[100] = {0};
    int n = 0;
    int i = 0;
    int tmp = 0;
    int sum = 0;

    scanf("%d", &n);

    while (n) {
        tmp = n % 10;
        if (tmp % 2 == 0) {
            arr[i] = 0;
        } else {
            arr[i] = 1;
        }
        n = n / 10;
        i++;
    }

    int j = 0;
    for (j = 0; j < i; j++) {
        sum = sum + arr[j] * (int)pow(10, j);
    }

    printf("%d", sum);
    return 0;
}