题解 | #二进制数#
二进制数
https://www.nowcoder.com/practice/103dd589fed14457a673c613d8de3841
关键在于 n%k n=n/k
#include<vector>
#include<cmath>
#include<iostream>
#include<cstdio>
using namespace std;
int main() {
int n;
vector<int> vec;
while (cin >> n) {
vec.clear(); //vec初始化
while (n != 0) {
vec.push_back(n % 2);
n = n / 2;
}
for (int i = vec.size() - 1; i >= 0; i--) {
cout << vec[i];
}
cout << endl;
}
}
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