题解 | #数值的整数次方#
数值的整数次方
https://www.nowcoder.com/practice/1a834e5e3e1a4b7ba251417554e07c00
class Solution { public: double Power(double base, int exponent) { double res=1; if(exponent==0) return 1; //先取绝对值计算幂,再判断正负 for(int i=1; i<=abs(exponent); i++){ res=res*base; } if (exponent>0) return res; else return 1/res; } };