题解 | #Skew数#

#include <cstdio>
#include <string>
#include <iostream> // 引入iostream以使用cin和cout
#include "cmath"
using namespace std;

int main() {
    string number;
    unsigned long long int answer = 0;
    unsigned long long int temp = 0;
    while (getline(cin, number) &&
            !cin.eof()) { // 使用cin代替number，并检查cin的状态
        string end="0";
        if(number==end){break;}
        for (int i = 0; i < number.size(); i++) {
            if (number[i] != '0') {
                temp = (pow(2, number.size() - i) - 1);
                answer = answer + (number[i] - '0') * temp;
            }
        }
        printf("%lld\n", answer);
        answer = 0;
    }


    return 0;
}