题解 | #记负均正II#

#include <stdio.h>
#include <string.h>
int main() {
    double a[2010];
    double sum = 0;
    int count = 0;
    int j = 0, i = 0;
    while (scanf("%lf ", &a[i]) != EOF) {
        if (a[i] >= 0) {
            sum += a[i];
            j++;
        }
        if (a[i] < 0)
            count++;
    }
    if (sum == 0)
        printf("%d\n%.1lf\n", count, sum);
    else
        printf("%d\n%.1lf\n", count, sum / j);
    return 0;
}