题解 | #记负均正#

#include <stdio.h>
#include <string.h>
int main()
{
    int n;
    scanf("%d",&n);
    double a[2010];
    double sum=0;
    int count=0;
    int j=0;
    for (int i = 0; i < n; i++) {
        scanf("%lf",&a[i]);
        if(a[i]>0)
        {
            sum += a[i];
            j++;
        }
        if(a[i]<0)
            count++;
    }
    if(sum==0)
        printf("%d %.1lf\n",count,sum);
    else
        printf("%d %.1lf\n",count,sum/j);
    return 0;
}