题解 | #A+B#

A+B

https://www.nowcoder.com/practice/b183eac8dfba4de99d47c1ca4ce9571f

#include <stdio.h>
#include <string.h>

int main() {
    char a[15];
    char b[15];
    while (scanf("%s %s", &a, &b) != EOF) { // 注意 while 处理多个 case
        // printf("%s:%d  ",a,strlen(&a));
        int i, j;
        long long A = 0;
        for (i = strlen(&a) - 1, j = 1; i >= 0; i--) {
            if (a[i] == ',' || a[i] == '-') {
                continue;
            }
            A += (a[i] - '0') * j;
            j *= 10;
        }
        if (a[0] == '-') {
            A = -A;
        }
        //printf("%d ", A);

        long long B = 0;
        for (i = strlen(&b) - 1, j = 1; i >= 0; i--) {
            if (b[i] == ',' || b[i] == '-') {
                continue;
            }
            B+= (b[i] - '0') * j;
            j *= 10;
        }
        if (b[0] == '-') {
            B = -B;
        }
        printf("%d\n", A+B);

        // printf("%s:%d\n",b,strlen(&b));
    }
    return 0;
}

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