题解 | #人民币转换#

#include <stdio.h>
#define YI_1 100000000
#define WAN_1 10000
#define QIAN_1 1000
char* _V[] = {"","壹","贰","叁","肆","伍","陆","柒","捌","玖","拾"};
//oFlag 1 千上有值 ， 0 千上无值
void printQ(int n,int oFlag)
{
    int qian = n / QIAN_1;
    int zeroFlag = 0;
    if(qian > 0)
    {
        printf("%s仟",_V[qian]);
        oFlag = 1;
    }
    if(qian == 0 && oFlag)
    {
        printf("零");
        zeroFlag = 1;
    }
    int bai = (n % QIAN_1) / 100;
    if(bai > 0){
        printf("%s佰",_V[bai]);
        oFlag = 1;
        zeroFlag = 0;
    }
    if(bai == 0 && (0 == zeroFlag) && oFlag)
    {
        printf("零");
        zeroFlag = 1;
    }
    int shi = n % 100;
    if(shi > 0)
    {
        if(shi/10 > 1)
            printf("%s拾",_V[shi/10]);
        else if(shi/10 == 1)
            printf("拾");
        if(shi/10 >= 1)
            zeroFlag = 0;
    }
    if(shi == 0 && (0 == zeroFlag) && oFlag)
    {
        printf("零");
        zeroFlag = 1;
    }
    int yuan = n % 10;
    if(yuan > 0)
        printf("%s",_V[yuan]);
  
}
void printWQ(int n,int oFlag)
{
    int wan = n / WAN_1;
    if(wan > 0)
    {
        printQ(wan,oFlag);
        printf("万");
    }
    //print q
    int qian = n % WAN_1;
    if(qian > 0)
    {
        printQ(qian,oFlag);
    }
}
void printJF(double d)
{
    int n = d * 10;
    n = d*1000;
    if(n%10 == 9)
    n+=1;
    n /=10;
    if(n/10 > 0)
        printf("%s角",_V[n/10]);
    //else
    //    printf("零");
    int f = n%10;
    if(f > 0)
        printf("%s分",_V[f]);       
}
int main() {
    double money;
    int n;
    double jf;
    int oFlag = 0;
    scanf("%lf",&money);
    printf("人民币");
    if(money <= 0)
    {
        printf("零元");
        return 0;
    }
    n = (int)money;
    jf = money - (float)n;
    //print yi
    int yi = n/YI_1;
    if(yi > 0)
    {
        oFlag = 1;
        printWQ(yi,0);
        printf("亿");
    }
    //print wq
    int wanq = (n%YI_1);
    if(wanq > 0)
    {
        printWQ(wanq,oFlag);
    }
    
    if(jf <= 0)
        printf("元整");
    else
    {
        if(money >= 1.0)
            printf("元");
        printJF(jf);
    }
    

    return 0;
}