题解 | #小乐乐改数字#

#include <stdio.h>
#include <math.h>
int main() {
      long long a = 0;
    scanf("%lld", &a);
    int count = 1;
    long long c = a;
    long long sum = 0;
    int i = 0;
    while (c / 10)
    {
        count++;
        c /= 10;
    }
    c = a;
    for (i = 0; i < count; i++)
    {
        int low = c % 10;
        if (low%2==0)
        {
            low = 0;
            sum +=(long long)pow(10, i)*low;
        }
        if (low % 2 != 0)
        {
            low = 1;
            sum += (long long)pow(10, i)*low;
        }
        c = c / 10;

    }
    printf("%lld\n", sum);

    return 0;
}