题解 | #牛牛的等差数列#
牛牛的等差数列
https://www.nowcoder.com/practice/fb9daba67b88437a9e501adf020d425e
#include <stdio.h>
int main() {
int a, b;
scanf("%d%d", &a, &b);
printf("%d\n", 2 * b - a);
return 0;
}
等差数列an=a1+(n-1)d, a1+a3=2a2
牛牛的等差数列
https://www.nowcoder.com/practice/fb9daba67b88437a9e501adf020d425e
#include <stdio.h>
int main() {
int a, b;
scanf("%d%d", &a, &b);
printf("%d\n", 2 * b - a);
return 0;
}
等差数列an=a1+(n-1)d, a1+a3=2a2
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