题解 | #N的阶乘#
N的阶乘
https://www.nowcoder.com/practice/f54d8e6de61e4efb8cce3eebfd0e0daa
import sys
def jiec(n):
if n<2:
return 1
return n*jiec(n-1)
for line in sys.stdin:
a = line.split()
# print(int(a[0]) )
print(jiec(int(a[0])))
可以使用python3，会自动将大数值转为字符运算
