题解 | #求int型正整数在内存中存储时1的个数#

#include <stdio.h>
//#include <math.h>
int main() {
    int a = 0x00;
    scanf("%d",&a);
    int count1 = 0;
    int temp = 0x00000001;//0x10000000;
    for(int i = 0; i < 32; i++)
    {
        //temp = pow(2,i);
        if(0 != ((temp << i) & a))
            count1++;
    }
    printf("%d",count1);
    return 0;
}