题解 | #a+b#

#include<iostream>
#include<string>
using namespace std;
void fuc(string s){
	
	int i = 0;
	while(s.at(i)!=' ')i++;
	char num1[10001];
	char num2[10001];
	char num3[10001];
	for(int j = 0;j<10001;j++){
		num1[j] = '0';
		num2[j] = '0';
		num3[j] = '0';
	}
	for(int j = 0;j<i;j++){
		num1[i-1-j] = s.at(j);
	}
	
	for(int j = s.length()-1;j>i;j--){
		num2[s.length()-1-j] = s.at(j);
	}
	
	int overflow = 0;
	for(int j = 0;j <10001;j++){
		int count = num1[j]-'0'+num2[j]-'0'+overflow;
		if(count>=10){
			overflow = 1;
			count = count - 10;
		}
		else overflow = 0;
		num3[j] = count+'0';
	}
	//转置输出
	int k = 10000;
	while(num3[k]=='0'){
	//	cout<<k<<' ';
		k--;
	}
//	cout<<"k is "<<k<<endl;
	while(k>=0){
		cout<<num3[k];
		k--;
	}
}
int main(){
	char buffer[10000];
	while(cin.getline(buffer,10000)){
		if(cin.eof())break;
		string s = buffer;
		fuc(s);
		
	}
	
	return 0;
}