题解 | #有效括号序列#
有效括号序列
https://www.nowcoder.com/practice/37548e94a270412c8b9fb85643c8ccc2
#
# 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
#
#
# @param s string字符串
# @return bool布尔型
#
class Solution:
def isValid(self , s: str) -> bool:
# write code here
list_stack = []
for letter in s:
if letter in ['{','[','(']:
list_stack.append(letter)
else:
if list_stack == []:
return False
else:
if list_stack[len(list_stack)-1] == '(' and letter != ')':
return False
elif list_stack[len(list_stack)-1] == '{' and letter != '}':
return False
elif list_stack[len(list_stack)-1] == '[' and letter != ']':
return False
else:
list_stack.pop(len(list_stack)-1)
if list_stack != []:
return False
else:
return True
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