题解 | #Johnson Counter#
Johnson Counter
https://www.nowcoder.com/practice/7ee6e9ed687c40c3981d7586a65bc22d
`timescale 1ns/1ns module JC_counter( input clk , input rst_n, output reg [3:0] Q ); always @ (posedge clk,negedge rst_n) begin if(!rst_n) Q <= {4{1'b0}}; else Q <= {~Q[0], Q[4-1:1]}; end endmodule