题解 | #把二叉树打印成多行# | Rust
把二叉树打印成多行
https://www.nowcoder.com/practice/445c44d982d04483b04a54f298796288
/**
* #[derive(PartialEq, Eq, Debug, Clone)]
* pub struct TreeNode {
* pub val: i32,
* pub left: Option<Box<TreeNode>>,
* pub right: Option<Box<TreeNode>>,
* }
*
* impl TreeNode {
* #[inline]
* fn new(val: i32) -> Self {
* TreeNode {
* val: val,
* left: None,
* right: None,
* }
* }
* }
*/
struct Solution{
}
impl Solution {
fn new() -> Self {
Solution{}
}
/**
* 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
*
*
* @param pRoot TreeNode类
* @return int整型二维数组
*/
pub fn Print(&self, pRoot: Option<Box<TreeNode>>) -> Vec<Vec<i32>> {
let mut ans = Vec::new();
if let Some(mut root) = pRoot {
let mut queue:VecDeque<Box<TreeNode>> = VecDeque::new();
queue.push_back(root);
while !queue.is_empty() {
let mut n = queue.len();
let mut item = Vec::new();
for i in 0..n {
let mut node = queue.pop_front().unwrap();
item.push(node.val);
if node.left.is_some() {
queue.push_back(node.left.unwrap());
}
if node.right.is_some() {
queue.push_back(node.right.unwrap());
}
}
ans.push(item);
}
}
return ans;
}
}
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