题解 | #合并区间#
合并区间
https://www.nowcoder.com/practice/69f4e5b7ad284a478777cb2a17fb5e6a
# class Interval:
# def __init__(self, a=0, b=0):
# self.start = a
# self.end = b
#
# 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
#
#
# @param intervals Interval类一维数组
# @return Interval类一维数组
#
class Solution:
def merge(self , intervals: List[Interval]) -> List[Interval]:
# write code here
if len(intervals) == 0:
return []
intervals.sort(key=lambda x: x.start)
ans = []
left, maxR = intervals[0].start, intervals[0].end
for i in range(1, len(intervals)):
if intervals[i].start > maxR:
ans.append(Interval(left, maxR))
left = intervals[i].start
maxR = max(maxR, intervals[i].end)
ans.append(Interval(left, maxR))
return ans
算法刷题记录 文章被收录于专栏
刷题,记录牛客的101

腾讯成长空间 5981人发布