题解 | #统计成绩#

#include <stdio.h>
int main() {
    int n;
    double A[100];
    double sum = 0;
    double p;
    scanf("%d", &n);
    for (int i = 0; i < n; i++) {
        scanf("%lf", &A[i]);
        sum = sum + A[i];
    }
    p = sum / n;
    double min, max;
    min = max = A[0];
    for (int i = 0; i < n; i++) {
        if (max < A[i])
            max = A[i];
        if (min > A[i])
            min = A[i];
    }
    printf("%.2lf %.2lf %.2lf", max, min, p);
    return 0;
}