题解 | #字符串排序#
字符串排序
https://www.nowcoder.com/practice/5af18ba2eb45443aa91a11e848aa6723
import sys
# 获取数量
num = int(input())
# 获取字符串
line_number = 1
arr = []
for line in sys.stdin:
if line_number <= num:
arr.append(line.split()[0])
line_number += 1
# 冒泡排序
for i in range(num):
for j in range(0, num - i - 1):
if arr[j] > arr[j + 1]:
arr[j], arr[j + 1] = arr[j + 1], arr[j]
# 输出
for s in arr:
print(s)
