题解 | #从单向链表中删除指定值的节点#

s = input().split()
N = int(s[0])
ls =[]
ls.append(s[1])

for i in range(1,N):
    v = s[2*i]
    pre = s[2*i + 1]
    ls.insert(ls.index(pre) + 1,v)

ls.remove(s[-1])
for k in ls:
    print(k,end=' ')