题解 | #简单计算器#

#include<stdio.h>
int main()
{
	double a, b;
	a = b = 0.0;
	char c;
	scanf("%lf%c%lf", &a, &c, &b);
	switch (c)
	{
	case '+':printf("%.4lf+%.4lf=%.4lf", a, b, a + b); break;
	case '-':printf("%.4lf-%.4lf=%.4lf", a, b, a - b); break;
	case '*':printf("%.4lf*%.4lf=%.4lf", a, b, a * b); break;
	case '/':if (b != 0.0)printf("%.4lf/%.4lf=%.4lf", a, b, a / b);
			else printf("Wrong!Division by zero!\n"); break;
	default:printf("Invalid operation!\n");
	}
	return 0;
}