题解 | #质数因子#

#include <iostream>
#include <cmath>
using namespace std;
int main(){
    long n,a;
    cin >> n;
    a = n;
    for(int i = 2; i <= sqrt(n); i++)
    {
        while (n % i == 0) {
            cout << i << " ";
            n /= i;
            continue;
        }
    }
    if(n -1 > 0) cout << n << endl;
    return 0;
}