题解 | #牛牛的金币#
牛牛的金币
https://www.nowcoder.com/practice/35d8e3e569dc49f2a1018d1dc9186998
#include<stdio.h>
int main()
{
int x, y = 0;
int x1, y1 = 0;
scanf("%d%d%d%d", &x, &y, &x1, &y1);
if (x1 - x == 0 && y1 - y == 1)
{
printf("u\n");
}
else if (x1 - x == 0 && y1 - y == -1)
{
printf("d\n");
}
else if (x1 - x == 1 && y1 - y == 0)
{
printf("r\n");
}
else if (x1 - x == -1 && y1 - y == 0)
{
printf("l\n");
}
return 0;
}
