题解 | #从尾到头打印链表#rust
从尾到头打印链表
https://www.nowcoder.com/practice/d0267f7f55b3412ba93bd35cfa8e8035
/** * #[derive(PartialEq, Eq, Debug, Clone)] * pub struct ListNode { * pub val: i32, * pub next: Option<Box<ListNode>> * } * * impl ListNode { * #[inline] * fn new(val: i32) -> Self { * ListNode { * val: val, * next: None, * } * } * } */ struct Solution{ } impl Solution { fn new() -> Self { Solution{} } /** * 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可 * * @param head ListNode类 * @return int整型一维数组 */ pub fn printListFromTailToHead(&self, head: Option<Box<ListNode>>) -> Vec<i32> { // write code here let mut result = Vec::new(); let mut current = head; //要用while let解构赋值 while let Some(node) = current { result.push(node.val); current = node.next; } result.reverse(); result } }
option 相关知识点
https://course.rs/basic/match-pattern/option.html
while let相关知识点
#rust#