题解 | #牛牛的计划#
牛牛的计划
https://www.nowcoder.com/practice/cf956ceef9f84f7393a0b7284fdbf95a
#include <stdio.h>
int main() {
int a,b,c,d,e,f;
scanf("%d %d %d",&a,&b,&c);
scanf("%d %d %d",&d,&e,&f);
if(d>a){printf("yes");}
else if(d==a){
if(e>b){printf("yes");}
else if(e==b){
if(f>=c){printf("yes");}
else printf("no");
}
else printf("no");
}
else printf("no");
return 0;
}
