题解 | #蛇形矩阵#
蛇形矩阵
https://www.nowcoder.com/practice/649b210ef44446e3b1cd1be6fa4cab5e
#include <stdio.h>
int main() {
int a, b,c,f;
scanf("%d",&a);
c=1;
while(c<=a&&c>=0)
{
for(b=1;b<=(a-c+1);b++)
{
if(b>0&&b!=(a-c+1)) //每行循环输出
printf("%d ",(((b+c-1)*(b+c-1)+(b+c-1))/2-c+1));
else if(b==(a-c+1)) //判断一行是输出结束
printf("%d\n",(((b+c-1)*(b+c-1)+(b+c-1))/2-c+1));
}
c++;
}
return 0;
}
