题解 | #牛牛的短信#
牛牛的短信
https://www.nowcoder.com/practice/435c9e2bf4f84bee99b82ce84e95b0b7
#include <stdio.h> void judge(int m,double* cost) { if(m<=60) { *cost+=0.1; } else { *cost+=0.2; } } int main() { int n; double cost=0; scanf("%d",&n); while(n) { int m; scanf("%d",&m); judge(m,&cost); n--; } printf("%lf",cost); return 0; }