题解 | #计算日期到天数转换#

#include<iostream>
using namespace std;
class Date {
  public:
    // 获取某年某月的天数
    int GetMonthDay(int year, int month) {
        int arr[13] = { 0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 };
        //闰年29天
        if (arr[month] == 28
                && ((year % 4 == 0 && year % 100 != 0) || (year % 400 == 0))) {
            return 29;
        }
        return arr[month];
    }
    //获取一年的天数
    int GetYearDay(int year, int month, int day) {
        int SumDay = 0;
        for (int i = 1; i <= month - 1; i++) {
            SumDay += GetMonthDay(year, i);
        }
        SumDay += day;
        return SumDay;

    }

  private:
    int _year;
    int _month;
    int _day;
};
int main()
{
	int a=0, b=0,c=0;
	Date d1;
	cin>>a>>b>>c;
	cout << d1.GetYearDay(a,b,c) << endl;
	return 0;
}