题解 | #旋转数组的最小数字#
旋转数组的最小数字
https://www.nowcoder.com/practice/9f3231a991af4f55b95579b44b7a01ba
import java.util.*; public class Solution { /** * 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可 * * * @param nums int整型一维数组 * @return int整型 */ public int minNumberInRotateArray (int[] nums) { // write code here if (nums.length < 2){ return nums[0]; } int left = 0; int right = nums.length - 1; int last = nums[nums.length - 1]; while (left < right){ int mid = (left + right) / 2; if (nums[mid + 1] < nums[mid]){ return nums[mid + 1]; } if (nums[mid] > last){ left = mid + 1; }else { right = mid; } } return nums[right]; } }