题解 | #牛牛的西格玛#
牛牛的西格玛
https://www.nowcoder.com/practice/c6b750ee8853484f8dbf14b9531b501f
#include <stdio.h> int sum(int n) { if(n>1) return sum(n-1)+n; else return 1; } int main() { int n; scanf("%d",&n); printf("%d",sum(n)); return 0; }
牛牛的西格玛
https://www.nowcoder.com/practice/c6b750ee8853484f8dbf14b9531b501f
#include <stdio.h> int sum(int n) { if(n>1) return sum(n-1)+n; else return 1; } int main() { int n; scanf("%d",&n); printf("%d",sum(n)); return 0; }
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