题解 | #牛牛的短信#
牛牛的短信
https://www.nowcoder.com/practice/435c9e2bf4f84bee99b82ce84e95b0b7
#include<iostream>
int main() {
unsigned int n, val;
float sum = 0.0;
scanf("%d", &n);
for (int i = 0; i < n; i++) {
scanf("%d ", &val);
if (val > 60) sum += 0.2;
else sum += 0.1;
}
printf("%.1f", sum);
return 0;
}
#菜狗的解题#
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