题解 | #图像相似度#

#include <iostream>
#include<iomanip>
using namespace std;
int main() {
    int a, b, c[100][100], d[100][100], count = 0, sum;
    cin >> a >> b;
    sum = a * b;
    for (int i = 0; i < a; i++) {
        for (int j = 0; j < b; j++) {
            cin >> c[i][j];
        }
    }
    for (int i = 0; i < a; i++) {
        for (int j = 0; j < b; j++) {
            cin >> d[i][j];
        }
    }
    for (int i = 0; i < a; i++) {
        for (int j = 0; j < b; j++) {
            if (c[i][j] == d[i][j])
                count++;
        }
    }
    cout << setiosflags(ios::fixed) << setprecision(2) << 100.0 * count / sum;
}