题解 | #日期差值#

日期差值

https://www.nowcoder.com/practice/ccb7383c76fc48d2bbc27a2a6319631c

#include <iostream>
using namespace std;
class Date
{
public:
    int GetMonthDay(int year, int month)
    {
        int array[13] = { 0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 };
        if (month == 2 && (year % 4 == 0 && year % 100 != 0 || year % 400 == 0))
        {
            return array[month] + 1;
        }
        return array[month];
    }
    Date(int year, int month, int day)
    {
        _year = year;
        _month = month;
        _day = day;
    }

    // <运算符重载

    bool operator < (const Date& d)
    {
        if (_year < d._year)
            return true;
        else if ((_year == d._year) && (_month < d._month))
            return true;
        else if (_day < d._day)
            return true;
        return false;


        
    }
    Date& operator+=(int day)
    {
        _day = _day + day;
        while (_day > GetMonthDay(_year, _month))
        {
            _day -= GetMonthDay(_year, _month);	
            _month++;
            if (_month > 12)
            {
                _year++;
                _month = 1;
            }

        }
        
        return *this;
    }
    Date& operator++()
    {
        *this += 1;
        return *this;
    }
    int operator-(const Date& d)
    {

        int day = 1;
        Date max = *this;
        Date min = d;

        if (*this < d)
        {
            max = d;
            min = *this;
        }
        while (min < max)
        {
            ++min;
            ++day;
        }
        return day;
    }
private:
    int _year;
    int _month;
    int _day;
};
int main() {
    int ayear,amonth,aday;
    int byear,bmonth,bday;
    scanf("%4d%2d%2d",&ayear,&amonth,&aday);
    scanf("%4d%2d%2d",&byear,&bmonth,&bday);
    Date d1(ayear,amonth,aday);
    Date d2(byear,bmonth,bday);
    int day = d1 - d2;

    cout << day << endl;

}
// 64 位输出请用 printf("%lld")

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