题解 | #链表内指定区间反转#
链表内指定区间反转
https://www.nowcoder.com/practice/b58434e200a648c589ca2063f1faf58c
import java.util.*; /* * public class ListNode { * int val; * ListNode next = null; * public ListNode(int val) { * this.val = val; * } * } */ public class Solution { /** * 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可 * * * @param head ListNode类 * @param m int整型 * @param n int整型 * @return ListNode类 */ public ListNode reverseBetween (ListNode head, int m, int n) { // write code here if(head != null && head.next != null && m != n) { ListNode cur = head; int tm = m, tn = n - m; //找到需要翻转区间的起始端点(s,e),和端点区间左右相邻点(left,right) ListNode left = null; while(tm-->1) { left = cur; cur = cur.next; } ListNode s = cur; while(tn-->0) { cur = cur.next; } ListNode e = cur; ListNode right = cur.next; //链表翻转 e.next = null; ListNode pre = null; cur = s; while(cur != null) { ListNode tmp = cur.next; cur.next = pre; pre = cur; cur = tmp; } //补齐: left->(e,s)->right if(left != null) { left.next = e; } s.next = right; //注意输出表头 return left == null ? e : head; } return head; } }