题解 | #字符串字符匹配#
字符串字符匹配
https://www.nowcoder.com/practice/22fdeb9610ef426f9505e3ab60164c93
s1 = input()
s2 = input()
for i in s1:
if i in s2:
continue
else:
print('false')
break #一旦出现s1的某个字符没有在s2中，直接跳出循环
else:
print('true')
