题解 | #二叉树的镜像#
二叉树的镜像
https://www.nowcoder.com/practice/a9d0ecbacef9410ca97463e4a5c83be7
struct TreeNode* Mirror(struct TreeNode* pRoot ) { if(!pRoot) return pRoot; struct TreeNode* temp=pRoot->left; pRoot->left=pRoot->right; pRoot->right=temp; if(pRoot->left)Mirror(pRoot->left); if(pRoot->right)Mirror(pRoot->right); return pRoot; }