题解 | #名字的漂亮度#
名字的漂亮度
https://www.nowcoder.com/practice/02cb8d3597cf416d9f6ae1b9ddc4fde3
n = int(input())
for i in range(n):
s = input()
score = 0
l1 = []
l2 = []
se = list(set(s))
ns = sorted(se, key=lambda c: -s.count(c)) # decs order
for c in ns:
l1.append(s.count(c))
for i in range(26): # full list of weight
l2.append(26-i)
for j in range(len(se)):
score += l2[j] * l1[j]
print(score)
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