题解 | #牛牛的短信#
牛牛的短信
https://www.nowcoder.com/practice/435c9e2bf4f84bee99b82ce84e95b0b7
#include <stdio.h>
int main() {
int n;
scanf("%d", &n);
int j;
int m;
float sum = 0;
for (j = 0; j < n; j++) {
scanf("%d", &m);
if (m > 60) {
sum += 0.2f;
} else
sum += 0.1f;
}
printf("%.1f", sum);
return 0;
}
