11.15笔试 第一题65%

路过的朋友们帮看看哪里有问题呢，测试案例都可以通过

import java.util.Scanner;

/** 测试案例
 * 5
 * 01.a.111111.2.22222.31.3.rc11.10.0b2222210.1.c11111
 *
 * 5
 * 1.2.02555 1.2.2555 1.2.ABA 1.2.0ABA 1.2.0ABA.C
 */

public class Main {
    public static void main(String[] args) {
        //读取输入并转换成字符串数组
        Scanner s = new Scanner(System.in);
        int n = s.nextInt();
        s.nextLine();
        String[] inputStrings = s.nextLine().split(" ");

        StringBuilder result = new StringBuilder();
        //用来标记是否前后相邻且 重复 string.equals()
        String cur = "";
        //对每个字符串进行判断是否 合法的版本号
        for (String word : inputStrings) {
            //判断前3个条件
            String afterRemoveHead0 = checkFisrtThreeRules(word);
            if (afterRemoveHead0 != null) {
                //第4个条件判断 是否和前一个重复
                if (!cur.equals(afterRemoveHead0)) {
                    result.append(afterRemoveHead0 + " ");
                    cur = afterRemoveHead0;
                }
            }
        }
        result.deleteCharAt(result.length() - 1);
        System.out.print(result.toString());
    }

    static String checkFisrtThreeRules(String s) {
        StringBuilder stringBuilder = new StringBuilder();
        //第一条规则，首先以英文点分割三段
        String[] split = s.split("\\.");
        if (split.length != 3) {
            return null;
        }
        //第2条规则，去除第三段包含 rc
        if (split[2].contains("rc")) {
            return null;
        }
        //第3条规则，去除有 英文字符的
        if (split[0].matches(".*[a-zA-Z].*") || split[1].matches(".*[a-zA-Z].*")) {
            return null;
        }

        //第5个条件 去除 前导0
        for (String parts : split) {
            stringBuilder.append(parts.replaceFirst("^0+", ""));
            stringBuilder.append('.');
        }
        stringBuilder.deleteCharAt(stringBuilder.length() - 1);
        return stringBuilder.toString();
    }
}