题解 | #KiKi求质数个数#
KiKi求质数个数
https://www.nowcoder.com/practice/d3a404ee0f8d41f98bf4707035d91086
#include <stdio.h>
#include <math.h>
int main() {
int i=101,j,s=0;
while (i<1000) {
j=2;
while (j<=sqrt(i) ){
if(i%j==0)break;
j++;
}
if (j>sqrt(i))s++;
i+=2;
}
printf("%d",s);
return 0;
}
