HJ17题解 | #坐标移动#
坐标移动
https://www.nowcoder.com/practice/119bcca3befb405fbe58abe9c532eb29
#include <iostream>
using namespace std;
int main() {
string input;
int x = 0, y = 0;
getline(cin, input);
// input = "A10;S20;W10;D30;X;A1A;B10A11;;A10;";
string tmp;
size_t pos = input.find(";");
while (pos != string::npos) {
tmp = input.substr(0, pos);
input = input.substr(pos + 1);
if (tmp.empty()) {
pos = input.find(";");
continue;
}
int size = tmp.size();
if (size != 2 && size != 3) {
pos = input.find(";");
continue;
}
// is = false;
string numStr = tmp.substr(1);
bool isLeagle = true;
int num = 0;
for (auto item : numStr) {
if (item < '0' || item > '9') {
isLeagle = false;
}
}
if (!isLeagle) {
pos = input.find(";");
continue;
}
if (tmp[0] == 'A') {
x += atoi(numStr.c_str()) * (-1);
} else if (tmp[0] == 'D') {
x += atoi(numStr.c_str()) * (1);
} else if (tmp[0] == 'W') {
y += atoi(numStr.c_str()) * (1);
} else if (tmp[0] == 'S') {
y += atoi(numStr.c_str()) * (-1);
} else {
}
pos = input.find(";");
}
cout << x << "," << y;
}
// 64 位输出请用 printf("%lld")
#刷题记录#
